minio/vendor/github.com/klauspost/reedsolomon/inversion_tree.go
Harshavardhana ed676667d0 vendor: update reedsolomon package with new changes. (#2870)
- Cached inverse matrices for better reconstruct performance.
- New error reconstruction required is returned, helpful in
  initiating healing.
2016-10-06 21:57:42 -07:00

161 lines
5.8 KiB
Go

/**
* A thread-safe tree which caches inverted matrices.
*
* Copyright 2016, Peter Collins
*/
package reedsolomon
import (
"errors"
"sync"
)
// The tree uses a Reader-Writer mutex to make it thread-safe
// when accessing cached matrices and inserting new ones.
type inversionTree struct {
mutex *sync.RWMutex
root inversionNode
}
type inversionNode struct {
matrix matrix
children []*inversionNode
}
// newInversionTree initializes a tree for storing inverted matrices.
// Note that the root node is the identity matrix as it implies
// there were no errors with the original data.
func newInversionTree(dataShards, parityShards int) inversionTree {
identity, _ := identityMatrix(dataShards)
root := inversionNode{
matrix: identity,
children: make([]*inversionNode, dataShards+parityShards),
}
return inversionTree{
mutex: &sync.RWMutex{},
root: root,
}
}
// GetInvertedMatrix returns the cached inverted matrix or nil if it
// is not found in the tree keyed on the indices of invalid rows.
func (t inversionTree) GetInvertedMatrix(invalidIndices []int) matrix {
// Lock the tree for reading before accessing the tree.
t.mutex.RLock()
defer t.mutex.RUnlock()
// If no invalid indices were give we should return the root
// identity matrix.
if len(invalidIndices) == 0 {
return t.root.matrix
}
// Recursively search for the inverted matrix in the tree, passing in
// 0 as the parent index as we start at the root of the tree.
return t.root.getInvertedMatrix(invalidIndices, 0)
}
// errAlreadySet is returned if the root node matrix is overwritten
var errAlreadySet = errors.New("the root node identity matrix is already set")
// InsertInvertedMatrix inserts a new inverted matrix into the tree
// keyed by the indices of invalid rows. The total number of shards
// is required for creating the proper length lists of child nodes for
// each node.
func (t inversionTree) InsertInvertedMatrix(invalidIndices []int, matrix matrix, shards int) error {
// If no invalid indices were given then we are done because the
// root node is already set with the identity matrix.
if len(invalidIndices) == 0 {
return errAlreadySet
}
if !matrix.IsSquare() {
return errNotSquare
}
// Lock the tree for writing and reading before accessing the tree.
t.mutex.Lock()
defer t.mutex.Unlock()
// Recursively create nodes for the inverted matrix in the tree until
// we reach the node to insert the matrix to. We start by passing in
// 0 as the parent index as we start at the root of the tree.
t.root.insertInvertedMatrix(invalidIndices, matrix, shards, 0)
return nil
}
func (n inversionNode) getInvertedMatrix(invalidIndices []int, parent int) matrix {
// Get the child node to search next from the list of children. The
// list of children starts relative to the parent index passed in
// because the indices of invalid rows is sorted (by default). As we
// search recursively, the first invalid index gets popped off the list,
// so when searching through the list of children, use that first invalid
// index to find the child node.
firstIndex := invalidIndices[0]
node := n.children[firstIndex-parent]
// If the child node doesn't exist in the list yet, fail fast by
// returning, so we can construct and insert the proper inverted matrix.
if node == nil {
return nil
}
// If there's more than one invalid index left in the list we should
// keep searching recursively.
if len(invalidIndices) > 1 {
// Search recursively on the child node by passing in the invalid indices
// with the first index popped off the front. Also the parent index to
// pass down is the first index plus one.
return node.getInvertedMatrix(invalidIndices[1:], firstIndex+1)
}
// If there aren't any more invalid indices to search, we've found our
// node. Return it, however keep in mind that the matrix could still be
// nil because intermediary nodes in the tree are created sometimes with
// their inversion matrices uninitialized.
return node.matrix
}
func (n inversionNode) insertInvertedMatrix(invalidIndices []int, matrix matrix, shards, parent int) {
// As above, get the child node to search next from the list of children.
// The list of children starts relative to the parent index passed in
// because the indices of invalid rows is sorted (by default). As we
// search recursively, the first invalid index gets popped off the list,
// so when searching through the list of children, use that first invalid
// index to find the child node.
firstIndex := invalidIndices[0]
node := n.children[firstIndex-parent]
// If the child node doesn't exist in the list yet, create a new
// node because we have the writer lock and add it to the list
// of children.
if node == nil {
// Make the length of the list of children equal to the number
// of shards minus the first invalid index because the list of
// invalid indices is sorted, so only this length of errors
// are possible in the tree.
node = &inversionNode{
children: make([]*inversionNode, shards-firstIndex),
}
// Insert the new node into the tree at the first index relative
// to the parent index that was given in this recursive call.
n.children[firstIndex-parent] = node
}
// If there's more than one invalid index left in the list we should
// keep searching recursively in order to find the node to add our
// matrix.
if len(invalidIndices) > 1 {
// As above, search recursively on the child node by passing in
// the invalid indices with the first index popped off the front.
// Also the total number of shards and parent index are passed down
// which is equal to the first index plus one.
node.insertInvertedMatrix(invalidIndices[1:], matrix, shards, firstIndex+1)
} else {
// If there aren't any more invalid indices to search, we've found our
// node. Cache the inverted matrix in this node.
node.matrix = matrix
}
}