Simplify HTTP trace related code (#7833)

This commit is contained in:
Krishna Srinivas
2019-06-26 22:41:12 -07:00
committed by kannappanr
parent c1d2b3d5c3
commit 183ec094c4
11 changed files with 176 additions and 265 deletions

View File

@@ -19,12 +19,19 @@ package pubsub
import (
"fmt"
"testing"
"time"
)
func TestSubscribe(t *testing.T) {
ps := New()
ps.Subscribe()
ps.Subscribe()
ch1 := make(chan interface{}, 1)
ch2 := make(chan interface{}, 1)
doneCh := make(chan struct{})
defer close(doneCh)
ps.Subscribe(ch1, doneCh, nil)
ps.Subscribe(ch2, doneCh, nil)
ps.Lock()
defer ps.Unlock()
if len(ps.subs) != 2 {
t.Errorf("expected 2 subscribers")
}
@@ -32,20 +39,33 @@ func TestSubscribe(t *testing.T) {
func TestUnsubscribe(t *testing.T) {
ps := New()
c1 := ps.Subscribe()
ps.Subscribe()
ps.Unsubscribe(c1)
ch1 := make(chan interface{}, 1)
ch2 := make(chan interface{}, 1)
doneCh1 := make(chan struct{})
doneCh2 := make(chan struct{})
ps.Subscribe(ch1, doneCh1, nil)
ps.Subscribe(ch2, doneCh2, nil)
close(doneCh1)
// Allow for the above statement to take effect.
time.Sleep(100 * time.Millisecond)
ps.Lock()
if len(ps.subs) != 1 {
t.Errorf("expected 1 subscriber")
}
ps.Unlock()
close(doneCh2)
}
func TestPubSub(t *testing.T) {
ps := New()
c1 := ps.Subscribe()
ch1 := make(chan interface{}, 1)
doneCh1 := make(chan struct{})
defer close(doneCh1)
ps.Subscribe(ch1, doneCh1, func(entry interface{}) bool { return true })
val := "hello"
ps.Publish(val)
msg := <-c1
msg := <-ch1
if msg != "hello" {
t.Errorf(fmt.Sprintf("expected %s , found %s", val, msg))
}
@@ -53,13 +73,17 @@ func TestPubSub(t *testing.T) {
func TestMultiPubSub(t *testing.T) {
ps := New()
c1 := ps.Subscribe()
c2 := ps.Subscribe()
ch1 := make(chan interface{}, 1)
ch2 := make(chan interface{}, 1)
doneCh := make(chan struct{})
defer close(doneCh)
ps.Subscribe(ch1, doneCh, func(entry interface{}) bool { return true })
ps.Subscribe(ch2, doneCh, func(entry interface{}) bool { return true })
val := "hello"
ps.Publish(val)
msg1 := <-c1
msg2 := <-c2
msg1 := <-ch1
msg2 := <-ch2
if msg1 != "hello" && msg2 != "hello" {
t.Errorf(fmt.Sprintf("expected both subscribers to have%s , found %s and %s", val, msg1, msg2))
}