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Merge pull request #348 from restanrm/remove-comment

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fix(machine): remove comment
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Kristoffer Dalby 2022-02-22 14:06:12 +00:00 committed by GitHub
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15
machine.go
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@ -167,21 +167,6 @@ func getFilteredByACLPeers(
peers := make(map[uint64]Machine) peers := make(map[uint64]Machine)
// Aclfilter peers here. We are itering through machines in all namespaces and search through the computed aclRules // Aclfilter peers here. We are itering through machines in all namespaces and search through the computed aclRules
// for match between rule SrcIPs and DstPorts. If the rule is a match we allow the machine to be viewable. // for match between rule SrcIPs and DstPorts. If the rule is a match we allow the machine to be viewable.
// FIXME: On official control plane if a rule allow user A to talk to user B but NO rule allows user B to talk to
// user A. The behaviour is the following
//
// On official tailscale control plane:
// on first `tailscale status`` on node A we can see node B. The `tailscale status` command on node B doesn't show node A
// We can successfully establish a communication from A to B. When it's done, if we run the `tailscale status` command
// on node B again we can now see node A. It's not possible to establish a communication from node B to node A.
// On this implementation of the feature
// on any `tailscale status` command on node A we can see node B. The `tailscale status` command on node B DOES show A.
//
// I couldn't find a way to not clutter the output of `tailscale status` with all nodes that we could be talking to.
// In order to do this we would need to be able to identify that node A want to talk to node B but that Node B doesn't know
// how to talk to node A and then add the peering resource.
for _, peer := range machines { for _, peer := range machines {
if peer.ID == machine.ID { if peer.ID == machine.ID {
continue continue